Competition Problem 83
by Ian Budden
What must West lead to allow South to make six spades and how is the contract then made against best subsequent defence?
Successful solvers: Jean-Marc Bihl, Steve Bloom, Ayhan Kök, Leigh Matheson, Sebastian Nowacki, Prahalad Rajkumar, Pavel Stříž, Daniel de Lind van Wijngaarden, Wim van der Zijden
The only losing lead for the defence is the ♣J.
South wins the ♣J with the ♣Q, and leads the ♣10 which West ducks (best). South cashes ♥A and continues with a diamond. West ducks and North discards. South leads another diamond, which North ruffs, whether or not West covers. North cashes the ♣A. on which South discards the ♥Q, then declarer ruffs two hearts and two diamonds, ending in North. North then leads his last side suit card and East is endplayed. If he ruffs low, South overruffs; and if he ruffs high, South discards his last diamond, forcing East to lead into the split spade tenace.
Play follows similar lines if West covers the second club or one or both of the diamond leads. The important point is that South must make only one natural diamond trick and ruff another one.
See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.
© Hugh Darwen, 2012
Date last modified: 11 March, 2017