Competition Problem 132b
South is declarer in six no-trumps. How is the contract made when West chooses the wrong queen for the opening lead?
Successful solvers: Steve Bloom, Ian Budden, Leigh Matheson, Radu Mihai, A.V. Ramana Rao, Zoran Sibinović, F.Y. Sing, Andries van der Vegt, Dick Yuen, Wim van der Zijden. Tables
West chooses the ♠Q. South wins and leads the ♣10. West does best to cover this and North wins, finessing. North leads the ♥J. East does best not to cover this but South wins with the ♥Q anyway. South’s next lead is the ♣7. West plays the ♣4 and North overtakes with the ♣8. The ♣A now starts a progressive seesaw squeeze on East in this position:
A. If East discards a spade, South plays low and comes to hand on the ♣9 to give up a spade. South’s heart loser goes on the second top diamond and then declarer comes to hand on the ♥A to score the established spade winners.
B. If East discards a diamond, South drops the ♣9 and North gives up a diamond trick. After a heart return to South’s ♥A, North’s heart loser goes on the top spade and the ♣3 affords entry to the good diamonds.
C. If East discards a heart, South again drops the ♣9 but now North cashes the ♣3 to continue the squeeze.
1. A spade discard allows the spades to be established with ♥10 as entry.
2. A diamond discard allows the diamonds to be established with the ♥A as entry.
3. Discarding the ♥K allows North to exert a second seesaw squeeze by leading the ♥6, South playing the ♥7 if East throws a spade, otherwise the ♥A.
See the solution to Competition Problem #4 for the recommended tabular format if you prefer not to write in English prose.
Hugh Darwen, 2015