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William
H. Whitfeld
The first of the two problems included in this article is generally referred to as The Whitfeld Six. I am sorry to note that the version appearing in my own book, Bridge Magic (1972) is the one mentioned in the article as having appeared in the London Field. Curiously, neither of these problems is included in Coffin's collection. I have reproduced the article faithfully, including the reversal of the minor suits in the problem diagrams. Whitfeld,
William H. The foremost inventor of double-dummy problems, and a whist
mathematician and analyst of great ability.
Mr. Whitfeld was born at Whist Villa, Mr. Whitfeld has been very fond of whist
from an early age. Though at no time a great frequenter of the whist-table, as
compared with some devotees of the game, he has devoted much spare time to
analyzing positions and working out problems.
His first contributions to whist literature consisted of some
double-dummy problems published in 1880 in the Cambridge Review, an
undergraduates' journal. His fame as a whist problemist was established,
however, by a double dummy problem which he sent to the R. F. Foster writes as follows concerning
the problem in the We give the problem herewith, in its original and correct form, together with the solution, as received from Mr. Whitfeld himself. In this case, as in all other problems, the solution should not be consulted until all efforts to work out the answer have failed, or until it is desired to verify a solution arrived at: ♠
None ♠ Q, 7
♠ J, 6 ♠
10, 9 Hearts trumps.
South to lead. The correct solution of the problem is as follows: Trick 1.¾South leads ace of diamonds, on which north plays jack. This is the key to the problem. Only by this play can north reserve the opportunity of playing a diamond through west and giving south a finesse, should the development warrant such a course. Trick 2.¾South leads ten of spades, which north wins with seven of hearts. Trick 3.¾North leads eight of hearts, on which south discards ten of clubs. West is obliged to unguard one of the plain suits. His best discard is the spade, since his partner also guards that suit. Trick 4.¾North plays ace of clubs, and east is compelled to unguard the spade or diamond suit. South, playing after east, keeps the suit from which east has discarded. Trick 5.¾North leads a diamond, which south wins with the king. Trick 6.¾South leads the thirteenth spade or diamond. It should be noticed that if at trick three west discards the queen of diamonds, he leaves south with the tenace over east, and if he discards a club, north will make his small club. We may add that the problem, since its
original publication, has frequently been republished in a somewhat altered or
disguised form. One of these variations was given in the London Field of
December 14, 1889, where the suits and some of the unimportant cards were
changed from the original. The The first publication of the problem in the
Field was followed by other interesting and difficult hands composed by Mr.
Whitfeld, as well as by articles on whist, in which his mathematical genius was
displayed in close reasoning and subtle analysis. In 1892 he became regularly
connected with the staff of the Field, and in 1893 he had entire charge of its
card department during " Cavendish's" absence in In closing this brief notice, we take pleasure in giving another one of his very best double-dummy problems; in fact, he himself considers it of nearly equal merit with his more celebrated achievement: ♠
9,7,6,3 ♠ None
♠ None ♠
None Spades are trumps.
South to lead. The correct solution of the problem is as follows: Trick 1. South leads a small heart, which north trumps. Trick 2. North leads a trump, forcing a discard from east. If he discards a heart, south will finally make a trick in that suit with the last heart. He must, therefore, discard a club or a diamond. The position of the cards in these two suits being in all essential respects similar, we need only take one case. We will suppose that he discards a club. South then also discards a club. Trick 3. North leads a club, which south wins. Trick 4. South leads the best heart, to which north discards a diamond. Trick 5. South leads a small heart, which north trumps. Trick 6. North leads the last trump. Unless east keeps his heart south will make the last heart. East must therefore discard a diamond. South then discards his heart. West is now in a difficulty. If he discards a club, north will take a trick with the last card of that suit, and if he discards a diamond his remaining one will fall to south's master card, and south's last diamond will win a trick. In either case, north and south win all the tricks. Not one player in fifty can solve it [the Whitfeld problem] without assistance. It seems remarkable that so difficult a combination could be set up with only six tricks. Whist, October, 1892. The problem which we gave on the sixteenth is generally known as the "Whitfeld" problem, and was composed by W.H. Whitfeld, "Cavendish's" understudy as whist editor of the London Field. "Cavendish" says it is the most difficult problem with six cards ever composed. Some persons call it the Proctor problem, but Proctor simply introduced it to this country. R.
F. Foster [S. O.], Sun, March 1, 1896.
© Hugh Darwen, 2009 Date last modified: 17 November, 2009 |